Question

Three years ago the sum of the ages of father and his son was 48 years and three years hence father's age will be three times that of his son. find the present ages of the father and his son.

Answer 1

son's age now=x

son's age 3 years ago= x-3

father's age 3 years ago was such that x-3+f=48;f=51-x

Therefore, father's age now is 51-x+3=54-x

I am assuming now the father's age is 3 times that of his son.

54-x=3x

4x=54

x=13.5 years ANSWER

father's age now is 40.5 years.

3 years ago, the ages were 10.5 and 37.5, and they add to 48.

++++====++++====+++

FOLLOW ME.

++++++=====++++==

Answer 2

Answ

Step-by-step explanation:

Let the present ages of the father and son be x years and y years respectively.

According to the question,

Condition I,

Three years ago the sum of the ages of the father and his son was 48 years.

or,(x−3)+(y−3)=48

or,x−3+y−3=48

or,x−6=48−y

or,x=54−y - (i)

Condition II,

Three years hence the father's age will be three times the son's age,

or,(x+3)=3(y+3)

or,x+3=3y+9 - (ii)

Put value of x from equation (i) in equation (ii), we get,

or,(54−y)+3=3y+9

or,54−y=3y+9−3

or,54−6=3y+y

or,48=4y

or,y=484

∴y=12

Put the value of y in equation (i), we get,

or,x=54−12

∴x=42

So, (x,y) = (42, 12)

Therefore, the required present ages of the father and the son are 42 years and 12