Question

Three years ago the sum of the ages of father and his son was 48 years and three years hence father's age will be three times that of his son. find the present ages of the father and his son.

1

Answer 1

Step-by-step explanation:

3years ago

F+S = 48

present age

F+S=48+3+3=54

AFTER 3 YEARS

3:1

(F+3)÷(S+3) = 3÷1

F+3 = 3S+9, or

F = 3S+6 …(2)

Equate (1) and (2): 54-S = 3S+6, or

4S=48, or S = 12 and So F = 42.

The father is 42 years and the son 12 years, now.