Math, asked by borkarnalanda20, 6 months ago

Three years hence a man age will be three times the size 8 years ago he was seven times as old how old are they now

Answers

Answered by ItsUDIT
37

ANSWER:

AGE OF MAN = 30 Years....

AGE OF SON = 5 Years.....

Step-by-step explanation..

Let the age of man be x

and the age of his son be y

According to the question:

After 6 years :

(x+6)=3(y+6)

⇒x−3y=12⟶(i)

Three years ago :

x−3=9(y−3)

⇒x−3=9y−27

⇒x−9y=−24⟶(ii)

Solving (i) and (ii),

6y=36

⇒y=6

Putting value of y in equation (i),

x−3xy=12

x−3xy=12∴x=12+18

x−3xy=12

x=12+18x=30

HENCE Age of man =30 years

HENCE Age of son =6 years.

HOPE THIS WILL HELP YOU.

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