Three years hence a man age will be three times the size 8 years ago he was seven times as old how old are they now
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ANSWER:
AGE OF MAN = 30 Years....
AGE OF SON = 5 Years.....
Step-by-step explanation..
Let the age of man be x
and the age of his son be y
According to the question:
After 6 years :
(x+6)=3(y+6)
⇒x−3y=12⟶(i)
Three years ago :
x−3=9(y−3)
⇒x−3=9y−27
⇒x−9y=−24⟶(ii)
Solving (i) and (ii),
6y=36
⇒y=6
Putting value of y in equation (i),
x−3xy=12
x−3xy=12∴x=12+18
x−3xy=12
x=12+18x=30
HENCE Age of man =30 years
HENCE Age of son =6 years.
HOPE THIS WILL HELP YOU.
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