Three years hence a man's age will be three times his son's age and 7 years ago he was 7 times as old as his son. How old are they now ?
Answers
Given : Three years hence a man's age will be three times his son's age and 7 years ago he was 7 times as old as his son
To Find : How old are they now
Solution:
Man's age = M Years
Son's Age = S Years
Three years hence man's age = M + 3 Years
Three years hence Son's Age = S+3 Years
Three years hence a man's age will be three times his son's age
=> M + 3 = 3(S + 3)
=> M + 3 = 3S + 9
=> M = 3S + 6
7 years Ago man's age = M -7 Years
7 years Ago Son's Age = S-7 Years
7 years ago he was 7 times as old as his son.
=> M - 7 = 7(S - 7)
=> M - 7 = 7S -49
=> M = 7S -42
3S + 6 = 7S -42
=> 4S = 48
=> S = 12
M = 3S + 6 = 3* 12 + 6 = 42
Man's Age = 42 Years
Son's Age = 12 Years
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