Question

three years ravi ago was 9 times as old as Sonu 6 and she will be twice as old as Sonu find the present age​

Answer 1

AnswEr:-

Present age of Ravi = 12 years.

Present age of Sonu = 4 years.

Step-by-step-explanation:-

☯Correct question :-

Three years ago Ravi was 9 times as old as Sonu.4 years after,Ravi will be twice as old as Sonu.Find their present ages.

☯Given :-

• 3 years ago,Ravi's age = 9 times Sonu's age.
• 4 years after,Ravi's age = 2 times Sonu's age.

☯To find :-

• Present age of Ravi = ?
• Present age of Sonu = ?

☯Solution :-

Let present age of Ravi be R years & present age of Sonu be S years.

☯ATQ:-

1st case:-

⇒ (R - 3) = 9(S - 3)

⇒ R - 3 = 9S - 27

⇒ R = 9S - 27 + 3

⇒ R = 9S - 24 ..............(Eq.1)

2nd case:-

➩ R + 4 = 2(S + 4)

➩ 9S - 24 + 4 = 2S + 8

➩ 9S - 20 - 2S = 8

➩ 7S = 8 + 20

➩ 7S = 28

➩ S = 28/7

➩ S = 4 years.

$\therefore\underbrace{\textsf{Present \: age \: of \: Sonu = {\textbf{4 \: years }}}}$

$\rule{200}{2}$

• Putting value of S in (Eq.1):-

➩ R = 9(4) - 24

➩ R = 36 - 24

➩ R = 12 years.

$\therefore\underbrace{\textsf{Present \: age \: of \: Ravi = {\textbf{12 \: years }}}}$

Answer 2

$\large \underline{ \red{ \boxed{ \bf \orange{Required \: Answer}}}}$