Three yrs ago the population of a town was 50000 if the annual increase during three successive yrs was at the rate 4%,5%,and 4% per annum respectively find the present population
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Solution: By using formula:
P(1+r¡/100)(1+r¡¡/100)(1+r¡¡¡/100)
where, P= Number of population
r¡=Rate of increment in 1st year.
r¡¡= ,,. ,,. ,,. ,,. 2nd year.
r¡¡¡=. ,,. ,,. ,,. ,,. 3rd year.
Now,. 50000(1+4/100)(1+5/100)(1+4/100)
= 50000(104/100)(105/100)(104/100)
= 5×104×105×104/100
=(104×105×104)/20
=56,784Answer
P(1+r¡/100)(1+r¡¡/100)(1+r¡¡¡/100)
where, P= Number of population
r¡=Rate of increment in 1st year.
r¡¡= ,,. ,,. ,,. ,,. 2nd year.
r¡¡¡=. ,,. ,,. ,,. ,,. 3rd year.
Now,. 50000(1+4/100)(1+5/100)(1+4/100)
= 50000(104/100)(105/100)(104/100)
= 5×104×105×104/100
=(104×105×104)/20
=56,784Answer
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