Question

thrice the sum of the quotient of acertain number and five divided by it the deffernce is 4.Find the number​

Answer 1

Step-by-step explanation:

Let the numbers be x and y.

We know that Dividend = Divisor × Quotient + Remainder

As per the statement, "If the sum of two numbers is divided by 15, the quotient is 2 and the

remainder is 10 , we get x+y=15×2+10=>x+y=40 --- (1)

Also, as the difference of the same numbers is divided by 3

then the quotient is 4 and the remainder is 2, we get x−y=3×4+2=>x−y=14 --- (2)

Adding

equations 1 and 2, we get 2x=54=>x=27

Substituting

x=27 in the equation (1), we get 27+y=40=>y=13

Thus the numbers are 27,13

Answer 2

Given:

Thrice the sum of the quotient of a certain number and five divided by it the difference is 4.

To find :

The number.

Solution:

Let the number be N, and the divisor is D, and the quotient is Q

The quotient = $\frac{N}{D}$

Thrice the sum of the quotient of a certain number and five is,

$3\frac{N}{D} + 5$

when divided by its difference is 4,

$\frac{3\frac{N}{D} + 5}{\frac{N}{D} - 5} = 4$

$\frac{\frac{3N+ 5D}{D} }{\frac{N-5d}{D} }$= 4

$\frac{3N+5D}{N-5D} = 4$

3N + 5D = 4(N - 5D)

3N + 5D = 4N - 20D

4N - 20D - 3N - 5D = 0

N - 25D = 0

N = 25D

Final answer:

The number is 25D