Question

THROUGH A DEVICE 5 COULOMB OF CHARGE FLOWS FOR 2 SECONDS . FIND THE POWER OF THE DEVICE IF THE VOLTAGE IS 240. ALSO FIND THE HEAT PRODUCED BY THE DEVICE

Answer 1

Answer:

Power = 600W,  Heat = 1200J

Explanation:

Given that,

Q = 5C

V = 240 V

Therefore,

Work Done (W) = VQ

                          = 240 * 5

                         = 1200 J

Therefore,

Power = W/t = 1200/2

                    = 600W

Current (I) = Q/t

                = 5/2 = 2.5 A

By Ohm's Law,

V = IR

R = V/I

R = 240/2.5

  = 96 Ω

By Joule's Law,

H = I²Rt

  = (2.5)² * 96 * 2

  =  1200J

I hope this helps you mate!