Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the field. If the width of each road is 3 metre,find
a) The area covered by the roads.
b) The cost of constructing the roads at the rate of rupees 110 per m ^2.
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Answer:441m²,₹48510
Step-by-step explanation:
length of the field = 90m
breadth of the field = 60m
from the diagram:
AD = SP = RQ = BC = 90m,
AB = HG = EF = CD = 60m
the width of the roads = 3m
so the area of the roads = (90 × 3)+(60×3)-(3×3)
= 270 + 180 - 9
441 m²
rate of cost = ₹110/m²
so total cost = ₹(441 × 110)
= ₹48510
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