Through a rectangular field of length 90cm and breadth 60m, two roads are constructed which are parallel to the sides at right angles through the center of the fields. if the width of each road is 3 m find
a} the area covered by the roads? b} the most of constructing the roads at the rate of Rs 110 per m?
15 points for the answer
Answers
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Given:-
Length of Rectangular field = 90m
Breadth of Rectangular field = 60m
Width of road at centre = 3m.
Need To Find:-
Area of Roads
cost of constructing the roads at the rate of ₹110 per m²
Where:-
L denotes Length
B denotes Breadth
Explanation:-
[Take a look at Attachment] In this Question, We are provided with the length of Rectangular field that is 90m and Breadth that is 60m and there is small road at centre of Rectangular field of 3m that is cuts at right angles through centre of fields.
Solution:-
PQ = 3m ; QR = 60m
EF = 90m ; FG = 3m
KL = 3m
⠀⠀
Area of Rectangular Road = QR × PQ
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 60 × 3
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 180m²
Hence, Area of Rectangular road is 180m2
∴Hence,AreaofRectangularroadis180m2
⠀⠀
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Now, We have to find the area Rectangular road EFGH.
Area of Rectangular road EFGH = L × B
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 90 × 3
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 270m²
Hence, Area of Rectangular road is 270m^2
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∴Hence, Area of Rectangular road is 270m2