Through a rectangular field of length 90m and breadth 60m, two roads are constructed which are parallel to the sides and cut each other at right angles through the center of the fields .If the width of each road is 3m,find the cost cost of constructing the roads at the rate rupees 110 per metre square
Answers
In Rectangular field :-
Length = 90cm(l)
Breadth = 60cm(b)
Area of the rectangular field = l*b
= 90*60
= 5,400 cm^2
Two roads are constructed in the rectangular field.
Width of the each road = 3cm
Area of the constructed road = (Area of the horizontal road + Area of the vertical road) - Area of the center of the square
:-
Area of horizontal road = l*b
= 90*3
= 270cm^2
Area of the vertical road = l*b
= 60*3
= 180cm^2
Area of the centre of the square =side*side
=3*3
=9cm^2
(270+180)-9
450-9
441cm^2
Rate of 1m^2 of construct roads=₹110
Rate of 441cm^2 = 441*110
Rate of 441cm^2 of construct road
= ₹48,510
Cost of constructing the roads of 441cm^2 is ₹48,510.
Hope it will useful to you and mark it as a brainliest solution..
Given:-
Length of Rectangular field = 90m
Breadth of Rectangular field = 60m
Width of road at centre = 3m
Need To Find:-
Area of Roads
cost of constructing the roads at the rate of ₹110 per m²
Where:-
L denotes Length
B denotes Breadth
Explanation:-
[Take a look at Attachment] In this Question, We are provided with the length of Rectangular field that is 90m and Breadth that is 60m and there is small road at centre of Rectangular field of 3m that is cuts at right angles through centre of fields.
Solution:-
PQ = 3m ; QR = 60m
EF = 90m ; FG = 3m
KL = 3m
⠀⠀
Area of Rectangular Road = QR × PQ
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 60 × 3
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 180m²
Hence, Area of Rectangular road is 180m2
∴Hence,AreaofRectangularroadis180m2
⠀⠀
_____________________________________
Now, We have to find the area Rectangular road EFGH.
Area of Rectangular road EFGH = L × B
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 90 × 3
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 270m²
Hence, Area of Rectangular road is 270m^2
∴Hence,AreaofRectangularroadis270m2
