through EDL n (n+1)(n+2) is divisible by 3
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Step-by-step explanation:
Since n is a positive integer taking b =3
We can write n = 3q + r , where q is some integer
n = 3q , n = 3q + 1 , n = 3q + 2
Case 1 = When n = 3q, n + 2 = 3q + 2 and n + 4 = 3q + 4 clearly only 3q is divisible by 3
Case 2 = When n = 3q + 1, n + 2 = 3q + 3 and n + 4 = 3q + 5 . Here also only n + 2 = 3q + 3 = 3(q + 1) is divisible by 3. Other two namely n and n + 4 are not divisible by 3.
Case 3 = When n = 3q + 2, n + 2 = 3q + 4 and n + 4 = 3q + 6 and in this case, only n + 4 = 3(q + 2) is divisible by 3
Hence only one out of n, n + 2 and n + 4 is divisible by 3 for any positive integer n .
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