Question

Through herons formula find The parallel sides of a Trapezium are 65 M and 40 M its non parallel sides are 39 and 56 M find the area of trapezium.​

Answer 1

Answer:

LET ABCD IS THE TRAPEZIUM WITH AD IS THE BOTTOM SIDE OF 65 m AND

BC THE TOP SIDE OF 40 m

PROJECT B AND C TO THE BOTTOM SIDE TO MEET IT E AND F RESPECTIVELY

LET ME TAKE E IS ON LEFT SIDE OF A

NOW BE = CF = H THE HEIGHT OF THE TRAPEZIUM

LET x BE THE DISTANCE AE

H^2 = [ 39^2 - x^2 ] = [ 56^2 - (25-x)^2 ]

SOLVING x = 19.8; AND H = 33.6

AREA OF TRAPEZIUM = H*(65+40)/2 = 33.6*52.5 = 1764 sqm

Step-by-step explanation:

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Answer 2

Answer:

semi perimeter =65+40+39+56 /2 =200/2 =100

area = [a+b/a-b] * √ [s-a]* [s-b]*[s-b-c]*[s-b-d]

=60+45/60–45 *√[100–65]*[100–40]*[100–40–56]*[100–40–39]

=105/25 √35*60*4*21 = 21/5 √176400 =21/5 *420 = 21*84 1764 m^2

Answer : Area =1764 M^2

Step-by-step explanation:

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