Question

through the midpoint m of the side cd of a parallelogram abcd, the line bm id drawn intersecting ad produced at e.prove that ae=2bc

Answer 1

since M is a part of CD and CD ll BA,
MD ll BA
so in triangle BAE , MD ll BA
so D is a midpoint of ED
DE=DA--------1
AD=BC
DE=DA=BC
FROM 1
AE=AD+DE
AE=2BC

HENCE THE proof

hope it is right


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