Through the midpoint m of the side cd of a parallelogram abcd
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See diagram.
ΔBCM & ΔEDM are similar. MD=CM => BC = DE, as AD = BC, AE = 2 BC
ΔACL & ΔAEL are similar. EL / BL = AE / BC = 2
So EL = 2 BL
Hope this helps you ☺️⭐✨✨⭐✌️✌️
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Answer:
Step-by-step explanation:See diagram.
ΔBCM & ΔEDM are similar. MD=CM => BC = DE, as AD = BC, AE = 2 BC
ΔACL & ΔAEL are similar. EL / BL = AE / BC = 2
So EL = 2 BL
Hope this helps you ☺️⭐✨✨⭐✌️✌️
Attachments:
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