Through two parallel wires A and B, 10A and 2A of currents are passed respectively in opposite directions. If the wire A is infinitely long and the length of the wire B is 2m, then force on the conductor B, which is situated at 10 cm distance from A, will be(a) 8 × 10⁻⁷ N(b) 8 × 10⁻⁵ N(c) 4 × 10⁻⁷ N(d) 4 × 10⁻⁵ N
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The forces will be opposite in nature. Due to opposite direction of the current.
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Answer:
B)8*10^5
* is multiplication and ^ is raised to
Pl. Excuse for the notations that cannot be typed due to limitations of device
Explanation:
The formula for calculating the force will be as follows...
So go ahead and solve it in three easy steps:
Formula: nu knot is a constant which is used in the starting ie, 4π×10^−7 so don't get surprised it's just a constant!
F=4π×10^−7÷4π × 2×i1×i2÷a × l
F=4π×10^−7÷4π × 2×10×2÷10×10^−2×2
On calculating,
F=8*10^5
Hopefully this shall help you. Do inform if there is any difficulty in the solution, keep learning!
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