Question

Thrown up from the top of a tower with aninitial velocity of 10m|s at angle of 30 with the horizontal it hits the grounds at a distance of 17.3 m from the base of tower calculate the height. of the tower

Answer 1

hey here is your answer ____

displacement in X direction =17.3

velocity in x direction=vcos¢

so 17.3=vcos¢t

17.3=√3 /2×10t

so t=1.99sec around 2sec

and displacement in y direction =-h

and velocity =vsin¢

so -h=vsin¢t-1/2gt^2

-h=10×1/2×2 -1/2×10×2×2

-h=10-20

-h=-10

so h=10m