Thrust of 'F' N is exerted on an area of 2A and thrust of '3F' N is exerted on an area A/2.Find the ratio of pressure exerted
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sorry i dont know but I wany point
satyam9692:
thrust is perpendicular force
Satyam not u
I mean that one should not post anything for getting points
ok sorry I thaught I am wrong
not u dear
ok
yes i put wrong ans
what
yo
@hero123421 sorry I can't give uh any points
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P1 = F/2A
P2 = 3F.2/A = 6F/A
on dividing both we get ratio = 1/12
.......
P2 = 3F.2/A = 6F/A
on dividing both we get ratio = 1/12
.......
Is this correct?
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