Ththe area of four walls of a cuboid box is 256 CM square if the length of the box is 5 times the height and breadth is three times the height find the dimensions of the cuboidal box
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So, let the Height be x
According to the Question,
Length is 5 times of height = 5x
Breadth is 3 times of height = 3x
Now,
2 [l+b]×h = 256
2 [5x + 3x] × x = 256
2 × 8x^2 = 256
16x^2 - 256 = 0
8 [2x^2 - 32] = 0 (Taking out 8 as common)
Now, through Factorization
2x^2 + 0x - 32 = 0
2x^2 + 8x^2 - 8x^2 - 32 = 0
[ 2x^2 + 8x^2 ] [ -8x^2 - 32 ] = 0
2x [x + 4] -8 [x + 4] = 0
[x + 4] [2x - 8] = 0
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• 2x - 8 = 0
2x = 8
x = 8/2 = 4
• x + 4 = 0
x = -4
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So,
X = 4
x = 4 (Sides Can't be Negative)
Henceforth,
Height = 4cm
Length = 5x = 5 × 4 = 20cm
Breadth = 3x = 3 × 4 = 12cm
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