Question

Thursday fell on which dates of april 2007 how to solve this

Answer 1

Answer:

Hi Friends,

Odd days of a year X = Remainder of [No. of days in the year X / 7].

[Where 7 --> For every 7 days, the day will be repeated, thats why we are dividing the total number of days of an year by 7. If it has any remainder then it will be considered as an odd day for that year.]

The required remainders (odd days) for the different years are given below:

For 2006: 365/7 = 1 (Total no. of days in 2006 is 365)

For 2007: 365/7 = 1

For 2008: 366/7 = 2 (Leap year, hence Feb month has 29 days)

For 2009: 365/7 = 1

Therefore, total number of odd days = 5.

Given day is 'Sunday' and total no of odd days is '5'.

The required date = Sunday + 5

= (The 5th day next to Sunday)