Question

Thus, the change in momentum of the hockey ball is 3 kg m sl.
0.14. A bullet of mass 10 g travelling horizontally with a velocity of 150 m si strikes a stationary wooden block
the magnitude of the force exerted by the wooden block on the bullet.
We will first calculate the acceleration (or rather retardation) of the bullet.​

Answer 1

Answer:

13.Mass of ball (m) = 200 g = 0.2 kg

Initial velocity of ball () = 10 m

Initial momentum of ball = = 0.2 kg x 10 m = 2 Ns

Final velocity of ball =- 5 m (Minus sign denotes that ball is moving in opposite direction.)

Final momentum of ball == 0.2 kg x -5 m =-1NS

Change in momentum = Final momentum - Initial momentum = 1Ns - 2Ns = 3N s. (Minus sign denotes change in momentum in the direction opposite to the direction of initial momentum of the ball.

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