Question

thw average of five consicutive natuaral numbets is 40 .then which is the smallest number?
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Answer 1

Answer:

Step-by-step explanation:

Allowing the numbers to be [math](n-4), (n-2), n, (n+2), (n+4)[/math], the average of them will be [math]n[/math], and the smallest of them will be [math](n-4).[/math]

Sum=[math](n-4)+(n-2)+n+(n+2)+(n+4)[/math]

Answer 2

Step-by-step explanation:

The average of 5 consecutive even numbers is 40. What is the smallest one?

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Its 4.

Allowing the numbers to be (n−4),(n−2),n,(n+2),(n+4) , the average of them will be n , and the smallest of them will be (n−4).

Sum= (n−4)+(n−2)+n+(n+2)+(n+4)

⟹ Sum= n+n+n+n+n−4+4−2+2

⟹ Sum= 5n

Average = 5n5

⟹ Average= n

So if 5n=40 , then n=8 , and n−4=4

Proof:

4+6+8+10+12=40

[math]\boxed{\text{The smallest number is 4.}[/math]