Question

Thwe zeroes of the quadratic polynomial x2-18x+81 are

Answer 1

Answer:

=x^2+(-9-9) x+81

=x (x-9)-9 (x-9)

=(x-9) (x-9) are the factors

Answer 2

Given:

x²-18x+81

To Find:

Two zeroes of the quadratic polynomial x²-18x+81.

Solution:

given quadratic equation is,

x²-18x+81.

by factorization,

⇒ x²-18x+81 = 0

⇒ x² -9x - 9x + 81 =0

⇒ x(x-9) -9(x-9) = 0

⇒ (x-9) (x-9) = 0

⇒ x-9 = 0

⇒ x =9

Hence, the two zeroes of the equation are 9 and 9.