tick the correct options for which the following pictures will be same on rotation
Answers
Answer:
This problem is a little unrealistic in that it really only provides two data points (initial and at 10 minutes). Graphical analysis would normally be done with many data points to reduce the effect of potential error in any of the points. But, on we go.
Some background (I want you to learn what is going on, not just get an answer!):
In first order decay, we find that if Ao is the inital concentration, A is the concentration at time t, A is related to Ao by
lnA = -kt + lnAo where k is the rate constant EQN. 1
Important: This is a linear form for which a plot of lnA vs. t is a straight line with a slope of -k and a y intercept of lnAo!
Another handy form of this equation is to express it in exponential form:
lnA - lnAo = -kt
ln(A/Ao) = -kt
A/Ao = e^(-kt)
A = Ao e^(-kt) EQN. 2
OK, since graphical analysis is requested …
Assume Ao = 1 M (t = 0). Then at t= 10 min, A = 1-.15Ao or A = 0.85Ao. = 0.85 M