Ticket numbered form 1 to 20 are mixed up together and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 7 ?
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Probability ✒ Probability is the measure of something which can be happen.
Probability = Number of Outcomes/Total Number of Outcomes
In this Question, it is given that Ticket numbered form 1 to 20 are mixed up together and then a ticket is drawn at random.
Total Number of Outcomes = 20
Possibility of Outcomes = { 1, 2, 3............, 20)
Multiple Number of 3 or 7 = { 3,6,9,12,15,18 ,5,10,15,20}
Let E be event of getting probability of Number
P(E) = Number of Outcomes / Total Number of Outcomes
P(E) = 9/20
Hence, Required Probability of the ticket drawn has a number is 9/20.
Probability ✒ Probability is the measure of something which can be happen.
Probability = Number of Outcomes/Total Number of Outcomes
In this Question, it is given that Ticket numbered form 1 to 20 are mixed up together and then a ticket is drawn at random.
Total Number of Outcomes = 20
Possibility of Outcomes = { 1, 2, 3............, 20)
Multiple Number of 3 or 7 = { 3,6,9,12,15,18 ,5,10,15,20}
Let E be event of getting probability of Number
P(E) = Number of Outcomes / Total Number of Outcomes
P(E) = 9/20
Hence, Required Probability of the ticket drawn has a number is 9/20.
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