ticket numbered from 1 to 20 are mixed up and a ticket is drawn at random. what is the probability that the ticket drawn has a number which is the multiple of 3 or 7
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Since, total tickets = 20
Multiples of 3 or 7 from 1 to 20 are:
3,6,7,9,12,14,15,18
∴ favorable outcomes=8
∴ required probability =
8/20 = 2/5
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