Question

ticket surface area of frustum of a cone is​

Answer 1

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⚡️⚡️TSA of a frustum of a cone = πl(r1 + r2) + πr12 + πr22

where l=slant height & r1 = radius of the base & r2 = radius of the top of frustum⚡️⚡️

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Answer 2

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$\bf\Huge\red{\mid{\overline{\underline{ ANSWER }}}\mid }$

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$\Large\fbox{\color{purple}{QUESTION}}$

SURFACE AREA VOLUME FORMULAS

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$\Large\fbox{\color{purple}{ SOLUTION }}$

$\Large\mathcal\green{FRUSTUM}$

$\implies \: tsa = \pi \: l(r1 + r2) + \pi \: {r1}^{2} + \pi {r2}^{2}$

$\implies \: tsa = \pi \: l(r1 + r2)$

$\implies volume = \frac{1}{3}\pi \: h( {r1}^{2} + r1.r2 + {r2}^{2} )$

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