Tickets marked R, Y, B, W are places on a tray. W Without looking, what is the probability of selecting: (a) a ticket marked W? (b) a ticket not marked W?
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Step-by-step explanation:
Part 1 - Tickets replaced after every trial
Number of ways of drawing 10 in 3 trials are
Trial 1 Trial 2 Trial 3 Number of Ways
5 5 0
2!
3!
=3
5 4 1 3!=6
5 3 2 3!=6
4 4 2
2!
3!
=3
4 3 3
2!
3!
=3
Number of ways of drawing 10 in 3 trials =3+6+6+3+3=21
Total number of ways of drawing in 3 trails =10
3
Therefore, probability of drawing 10 in 3 trials =
1000
21
Part 2: Tickets are not replaced after each trial
Buddy hope it give you any hint
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