Tickets numbered 1-30 are mixed uo together and then a ticket i drawn at random. What is the probability that the ticket is drawn will be multiple of 7???
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Answer:
the probability is 2/15
Step-by-step explanation:
n(S)= 30 (total outcomes)
Outcomes favorable to the event 'E' of the ticket being a multiple of 7 :
7,14,21, and 28
=> n(E)= 4 (no. of favourable outcomes)
Now, probability of occurence of event P(E) = n(E)/n(S)
= 4/30
=2/15
Hope I was able to help!1
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