Tickets numbered 1 to 100 are placed in a box. Find the probability that a ticket selected at random has a number that is divisible by both 2 and 5
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Step-by-step explanation:
50 tickets are numbered with even numbers so they are divisible by 2 in between 1 to 100
now we see the multiple of 5 which are odd
we will not see even because we have already counted them
so numbers divisible by 5 will be 5,15,25,35,45,55,65,75,85,95
total multiple of 5 are 10
all total number divisible by 2 and 5 = 50+10 =60
now applying formula we get,
60 / total number of tickets
= 60/100
= 6/10
= 3/5
so thats the prpbabilty pls click on heart button if u understand it....
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