Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random what is the probability that the ticket drawn bears a number which is a multiple of 3
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6/20=3/10..........is the probability .
sujataswami26:
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S={ 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19}
n(S)=20
let A is event that ticket drawn bears multiple of 3
A={3 6 9 12 15 18}
n(A)= 6
P(A)=n(A)/n(S)
= 6/20
=3/10
n(S)=20
let A is event that ticket drawn bears multiple of 3
A={3 6 9 12 15 18}
n(A)= 6
P(A)=n(A)/n(S)
= 6/20
=3/10
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