Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random what is the probability that the ticket drawn has a number which is a multiple of 3 and 7 y
pushkarbhau12:
7y Means what
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fossible outcome of getting number which is multiple of 3 and 7 are....
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probability = o÷20=0
(there is no number which are multiple by both 3 and 7 between 1 to 20)
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probability = o÷20=0
(there is no number which are multiple by both 3 and 7 between 1 to 20)
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