Question

Tickets Numbered 1 to 20 are shuffled what is the probability that a ticket drawn at random bears a numbers that is a multiple of Four

Answer 1

Answer:

Step-by-step explanation:

otal number of outcome n(s)=20

no of event n(E)=5, {4,8,12,16,20 are the multiple of 4}

therefore probability P(E)= n(E)/n(s)= 5/20

= 1/4 ans

pls mark as brainlist

multiples of 3 -  3 , 9, 12, 15 , 18 .

multiples of  5 - 5 , 10 , 15 , 20.

multiples of both 15.

total - 20

probability of multiple of 3  n(a)  - 5/20

probability of multiple of 5 n(b)  - 4/20

probability of both 3 and 5  n(a and b) - 1/20

probability of mulitple  3 or 5  n(a) + n(b) - n(a and b)

= 5/20 + 4/20 - 1/20  

=8/20

= 2/5

Answer 2

Answer:1/4

Step-by-step explanation:

Total possible outcomes=20

Favorable outcomes=multiples of four

There are 5 multiples of 4 till 20 namely 4,8,12,16,20

Probability=5/20=1/4

Pls mark as brainliest