Question

Tickets numbered 1 to 30 are mixed up and then a ticket is drwan at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5? *

Answer 1

Answer S={30}

Let event A be the probability that the ticket has the number which is multiple of 3 and 5

A={3,6,9,12,15,18,21,24,27,30,5,10,20,25}

Therefore n(A)=14

Therefore p(A)=n(A)/n(S)

Therefore p(A)=14/30=2.142~2.15

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