Question

Tickets numbered 1 to 50 are mixed and one ticket is drawn at random. Find the probability that the ticket drawn has a number which is a multiple of 4 or 7?​

Answer 1

Answer:

P(E) = n(E)/n(S) = 18/50= 9/25.

Answer 2

Answer :-

Multiples of 4 from 1 to 50 :- 4 , 8 , 12 , 16 ,20 , 24 , 28 , 32 , 36 , 40 , 44 , 48.

• Number of mutiples of 4 = 12

Multiples of 7 from 1 to 50 :- 7 , 14 , 21 , 28 , 35 , 42 , 49.

• Number of multiples of 7 = 7

Total number of multiples of 4 and 7 = 12 + 7 = 19.

Also, there is one common mutiple of 4 and 7 i.e. 28. So,

→ Number of multiples of 4 and 7 = 19 - 1 = 18

Hence, Favourable outcomes = 18

As there are 50 numbers,

→ Total number of outcomes = 50

We know that,

→ Probability = Favourable outcomes / Total number of outcomes

→ Probability = 18 / 50 = 9 / 25

Hence, the probability that the ticket drawn has a number which is a multiple of 4 or 7 is 9 / 25.