Question

Tickets numbered from 10 to 25 are mixed up together and then a ticket is

withdrawing at random. Find the probability that ticket has a number which

is multiple of 2 or 3.​

Answer 1

Answer:

6/16=3/8

Step-by-step explanation:

hope this helps u

Answer 2

Answer:

$\large{\boxed{\boxed{\sf{Question}}}}$

• Tickets numbered from 10 to 25 are mixed up together and then a ticket is withdrawing at random. Find the probability that ticket has a number which is multiple of 2 or 3.

Given :-

• Tickets numbered from 10 to 25 are mixed up together.

To find :-

• The probability that ticket has a number which is multiple of 2 or 3.

Formula used :-

$\bf \:Probability \: of \: an \: event =\dfrac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: outcomes \: in \: sample \: space} </p><p>$

OR

$\bf \:P(A) = \dfrac{n(A)}{n(S)}$

Where,

• P(A) is the probability of an event “A”
• n(A) is the number of favourable outcomes
• n(S) is the total number of events in the sample space

Solution :-

Tickets numbered from 10 to 25 are mixed up together.

Total number of tickets in Sample Space = n(S) = 16

Number which is multiple of 2 or 3 from 10 to 25 are

{10, 12, 14, 15, 16, 18, 20, 21, 22, 24}

⇛ Toral number of favourable outcomes, n(A) = 10

The probability that ticket has a number which is multiple of 2 or 3 is evaluated by using formula

$\bf \:Probability \: of \: an \: event =\dfrac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: outcomes \: in \: sample \: space} </p><p>$

$\bf\implies \:the \: probability \: that \: ticket \: has \: a \: number \: which \: is \: multiple \: of \: 2 \: or \: 3 = \dfrac{10}{16}$

$\bf\implies \:\dfrac{5}{8}$