Tickets numbered from 1to 20 are mixed up in a box and then a ticket is drawn at random. What is the probability that the ticket has a number which is a multiple of 3or7?
Answers
Answered by
1
Step-by-step explanation:
Since, total tickets = 20
Multiples of 3 or 7 from 1 to 20 are:
3,6,7,9,12,14,15,18
∴ favorable outcomes=8
∴ required probability =
20
8
=
5
2
Answered by
0
Answer:
Step-by-step explanation:
total number of tickets is 20
multiples of 3 lesser than 20 is 3,6,9,12,15,18
multiples of 7 is 7,14
hence v have
(prob of multiples of 3+ prob of multipl of 7)/prob of pickin any ticket
6+2/20=8/20=2/5
brainliest it..if it was helpful
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