Question

tickets numbers 1 to 20 are shuffled.what is the probability that a ticket drawn at random Bears a number that is a multiple of 4


" with answers"​

Answer 1

multiple of 4 in no. between 1 to 20 = 4, 8, 12, 16, 20

hence no. of favourable outcome is 4

total outcome = 20

probability = favourable outcome/total outcome

$\frac{5}{20} = \frac{1}{4}$