Tickets to a play cost $4 in advance and $5 at the door. The theater club president wants to raise at least $400 from the ticket sales. If the club sells 40 tickets in advance, what is the least number of tickets the club needs to sell at the door to reach the president’s goal?
Answers
Answer:
he needs to sell 80 tickets
Answer:
The Least Number of tickets the club needs to sell at the door to reach the president’s goal is 48.
Explanation:
What is Arithmatic Problems ?
This area contains percent problems, decimal identification, addition, subtraction, multiplication, and division as well as fraction and percent equivalences and estimate issues.
The arithmetic questions measure your proficiency in three key areas:
- Fractional and whole number operations.
- Using decimals and percents in operations.
- Using applications and fixing issues.
Verbal reasoning is the comprehension and reasoning of ideas expressed in language. Instead of focusing just on fluency or word knowledge, it seeks to assess the student's capacity for critical thought.
Tickets cost in advance is $4.
Ticket cost in door is $5
Total money to raise is $400.
40 tickets are sold in advance
Revenue generated = 40 *4 = $160
Revenue left to generate is $(400-160) = $ 240
Number of tickets sold in the door is = 240 / 5 = 48.
Number of tickets the club needs to sell at the door to reach the president’s goal is 48.
To know more about Arithmatic Problems and Verbal reasoning refer to:
https://brainly.in/question/28472757?referrer=searchResults
https://brainly.in/question/50650039?referrer=searchResults
#SPJ3