Tickets to a play cost $4 in advance and $5 at the door. The theater club president wants to raise at least $400 from the ticket sales. If the club sells 40 tickets in advance, what is the least number of tickets the club needs to sell at the door to reach the president’s goal? (Step by step with inequalities please.)
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Step-by-step explanation:
Let n be number of tickets at the door.
Let m be number of tickets in advance.
Revenue obtained at the door would be $5×n.
Similarly revenue in advance would be $4×m.
To raise $400, 5n+4m≥400
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Answer:
he need to sell 80 $
Step-by-step explanation:
hope its help
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