Question

Tickets to the high school reunion cost $35 with a meal and $25 without a meal. The reunion committee sells 70 tickets for $2,250.
How many tickets of the type without a meal were sold?

Answer 1

Answer:

Hi dezz

the number of ticket within meal is 50

and number of tickets without meal is 20

Step-by-step explanation:

50×35$ +20×25$ = 2250$

Answer 2

The required answer is 20.

As per the question we need to find the how many tickets of the type without a meal.

The given data is tickets to the high school reunion cost $35 with a meal and $25 without a meal. The reunion committee sells 70 tickets for $2,250.

Let y tickets of the type without a meal were sold,and x tickets of the type with a meal were sold.

Then according to the question we conclude that

x + y = 70,............ (1)

$35x+$25y = $2250..........(2)

from equation 1 we get

x = 70-y,

Now put the x value in 2 we get

35(70-y) + 25y =2250

2450 -35y+25y = 2250,

2450-2250 =10y

200=10y

y=20.

Hence the required answer is 20.

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https://brainly.com/question/14825956?

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