tickets to the school dance cost $3 in advance or $5 at the door. there was a total of 184 tickets sold, raising $688. how many tickets were sold at the door?
Answers
Answer:
68 tickets
Step-by-step explanation:
Let the tickets sold in advance - x
The tickets sold at the door - 184 - x
A.T.Q
3x + 5 (184 - x) = 688
3x + 920 - 5x = 688
3x - 5x = 688 - 920
-2x = - 232
2x = 232
x = 116
Tickets sold in advance = 116
Tickets sold at door = 184 - 116 = 68
Given :- Tickets to the school dance cost $3 in advance or $5 at the door. there was a total of 184 tickets sold, raising $688. how many tickets were sold at the door ?
Solution :-
Let us assume that, ticket sold at door was x .
then,
→ Ticket sold in advance = (184 - x) .
So,
→ sum raise in advance + sum raise in door = 688
→ 3(184 - x) + 5 * x = 688
→ 552 - 3x + 5x = 688
→ 2x = 688 - 552
→ 2x = 136
→ x = 68 (Ans.)
Hence, tickets were sold at the door were 68.
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