Question

TICS
51. The compound interest on Rs. 1000 at
10% per annum for 2 years is :
(A) Rs. 1210
(B) Rs. 210
(C) Rs. 200
(D) Rs. 190​

Answer 1

Answer:

B. 210

Step-by-step explanation:

■ Given■

Principal=Rs.1000

Rate of interest= 10% p.a.

Time= 2yrs

#For first year----

Time =1 year

S.I = P×R×T÷100

= 1000×10×1÷100

=Rs.100

Amount= Rs. 1100

# For second year---

Principal= Rs.1100

Rate of interest= 10%

Time =1 year

S.I = Rs. 110

Amount = Rs.1210

Therefore,

C.I= Rs.210

Answer 2

Answer:

1210

Step-by-step explanation:

Given

P = 1000

R = 10%p.a.

t = 2 years

sol :-

$c.i. = p(1 + \frac{r}{100} ) {}^{n}$

$\: \: \: \: \: \: = 1000(1 + \frac{10}{100} ) {}^{2}$

$\: \: \: \: \: = 1000( \frac{11}{10 } ) {}^{2}$

$\: \: \: \: = 1000 \times \frac{11}{10} \times \frac{11}{10}$

$\: \: \: \: \: = 1210$