Question

tiestions
1. The mass per unit volume of a
substance is called density.
(density mass/volume).
Arrange the following in order of
increasing density - air, exhaust
from chimneys, honey, water,
chalk, cotton and iron.​

Answer 1

Answer:

Air , Exhaust from chimney , Water , Honey , Cotton , Chalk , Iron.

This is the correct order

hope it helps you

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Answer 2

Answer:

thsnks dedo

The numerator of a fraction is 4 less than it's denominator. If 1 is added to both it's numerator and Denominator. Then, it becomes 4/12. Find the fraction.

\rule{100px}{.3ex}

❍ Let the Denominator of the fraction be x respectively.

Then, it's Numerator = (x – 4).

⠀

\underline{\bigstar\:\boldsymbol{According\;to \;the \;given\; Question \;:}}

★AccordingtothegivenQuestion:

⠀

If 1 is added to both it's numerator and Denominator. Then, it becomes 4/12.

⠀

Therefore,

⠀

\begin{gathered}:\implies\sf \dfrac{(x - 4) + 1}{x + 1} = \dfrac{4}{12}\\\\\\:\implies\sf \dfrac{x - 3}{x + 1} = \dfrac{4}{12} \\\\\\:\implies\sf 12(x - 3) = 4(x + 1)\\\\\\:\implies\sf 12x - 36 = 4x + 4\\\\\\:\implies\sf 12x - 4x = 4 + 36\\\\\\:\implies\sf 8x = 40\\\\\\:\implies\sf x = \cancel\dfrac{40}{8}\\\\\\:\implies{\underline{\boxed{\frak{\pink{x = 5}}}}}\;\bigstar\end{gathered}

:⟹

x+1

(x−4)+1

=

12

4

:⟹

x+1

x−3

=

12

4

:⟹12(x−3)=4(x+1)

:⟹12x−36=4x+4

:⟹12x−4x=4+36

:⟹8x=40

:⟹x=

8

40

:⟹

x=5

★

⠀

Hence,

⠀

Numerator of fraction, (x – 4) = (5 – 4) = 1

Denominator of fraction, x = 5

⠀

\therefore{\underline{\sf{Hence, \;the\; required\; fraction\;is\;\bf{\dfrac{1}{5}}.}}}∴

Hence,therequiredfractionis

5

1

.

\rule{250px}{.3ex}

V E R I F I C A T I O N :

If 1 is added to both it's numerator and Denominator. Then, it becomes 4/12. Let's verify :

\begin{gathered}\dashrightarrow\sf \dfrac{1}{5} = \dfrac{4}{12} \\\\\\\dashrightarrow\sf \dfrac{1 + 1}{5 + 1} = \cancel\dfrac{4}{12} \\\\\\\dashrightarrow\sf \cancel\dfrac{2}{6} = \cancel\dfrac{2}{6} \\\\\\\dashrightarrow\underline{\boxed{\frak{ \dfrac{1}{3} = \dfrac{1}{3}}}}\end{gathered}

⇢

5

1

=

12

4

⇢

5+1

1+1

=

12

4

⇢

6

2

=

6

2

⇢

3

1

=

3

1

\qquad\quad\therefore{\underline{\textsf{\textbf{Hence, Verified!}}}}∴

Hence, Verified!