Question

Tiles of length 75 cm and breadth 60 cm
are used to make the flooring of a house
How many such tiles are required if the
floor is 120 m long and 22.5 m wide?​

Answer 1

Answer:

The area of floor is = length × breadth

= 12000 × 2250

= 27000000 cm2

Area of one tile = length × breadth

= 75 × 60

= 4500 cm2

Tiles required = 27000000/4500

= 6000

the tiles required 6000

I hope that it will help you

thanx

Answer 2

Answer:

Given,

Length of the tile = 75cm

Breadth of the tile = 60cm

Length of the floor = 120m

Width of the floor = 22.5m

Tiles required = ?

So, we have to find the area

Area of the tile = Length × Breadth

= 75cm × 60cm

= 4500cm²

Area of the floor = Length × Width

= 120m × 22.5m

= 2700m²

Make metre and cm common that is converting metre → centimetre

2700m² → cm²

m² = m × m

1m² = 1m × 1m

1m = 100 cm

1m² = 100cm × 100cm = 1000cm²

2700m² = 2700 × 1m²

= 2700 × 1000cm²

= 27000000cm²

Now divide 27000000cm² by 4500cm²

No. of tiles required =27000000cm²

= 4500cm²

= 6000 cm²

Therefore, 6000 tiles required.

Hope this may help you…