tiles of side 24cm are required to cover the floor of room with dimensions 6.4 cm and 4.2cm?
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Area to be whitewashed = area of four walls + area of ceiling
Formulas to be noted :−
Area of four walls =2 ( length + breadth ) × height
Area of ceiling = area of rectangle = length × breadth
In the question, length of the room =6m
breadth of the room =4.5m
height of the room =3m
On the basis of formulas given above :−
Area of four walls =2(6m+4.5m)x3m
Area of four walls =2(10.5m)x3m
Area of four walls =21mx3m
Area of four walls =63m
2
Area of ceiling =6m×4.5m
Area of ceiling =27m
2
Therefore, area to be whitewashed =63m
2
+27m
2
Area to be whitewashed =90m
2
Cost of whitewashing = rate at which area is being whitewashed × area to be whitewashed
Cost of whitewashing =Rs8/m
2
×90m
2
Cost of whitewashing =Rs8×90
Cost of whitewashing =Rs.720.
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