Question

Tim has a bad of 36-orange sweets and Peter has a bad of 44-grape sweets. They have to divide up the sweets into small trays with equal number of sweets. If there is no remainder, find the largest possible number of sweets in each tray. GCF/LCM (circle)

Answer 1

Answer:

4 by the method of GCF

GCF of 36 and 44 is 4

Answer 2

Answer:

4 by the method

Step-by-step explanation:

4 by the method of gcf

GCF of 36 and 44 is4