Tim has a bag of 36 orange-flavoured sweets and Peter has a bag of 44 grape-flavoured sweets. They have to divide up the sweets into small trays with equal number of sweets; each tray containing either orange-flavoured or grape-flavoured sweets only. If there is no remainder, find the largest possible number of sweets in each tray.
Answers
Answered by
19
Answer:
each bag 18 orange sweets
Answered by
3
Given:
Number of orange-flavored sweets = 36
Number of grape-flavored sweets = 44
To find:
Largest possible number of sweets in each tray
Solution:
To find the largest possible number of sweets in each tray, we need to find the highest common factor of 36 and 44.
HCF of two numbers refers to the greatest number which can divide the given numbers.
Factors of 36 = 1 , 2 , 4, 6, 18, 36
Fcators of 44 = 1, 2, 4, 11, 22, 44
The common factors are 1, 2, 4
The highest among the common factors is 4
Hence, the largest possible number of sweets in each tray is 4.
Similar questions