Math, asked by asdfghjjhbgfd55, 6 months ago

Tim is buying packages of paper plates and cups. He wants to have equal amounts of each, but plates come 24 per pack, and cups come 16 pe What is r pack.the least amount of plates and cups Tim will have to buy to get the same number of each?
A.)
B.)
C.)
D.)

Answers

Answered by rajivdani20p3mkqi
2

Answer:

48

Step-by-step explanation:

in this situation we have to do HCF

16 = 2×2×2×2

24 = 2×2×2×3

So,HCF = 2×2×2×2×3

= 48.

I hope you understand the answer.

If not ask in comment.

please rate it as best answer.

Answered by aleenaakhansl
1

option d ) 48.

The least amount of plates and cups Tim will have to buy to get the same number of each is 48

CORRECT QUESTION:

Tim is buying packages of paper plates and cups. He wants to have equal amounts of each, but plates come 24 per pack, and cups come 16 pe What is r pack.the least amount of plates and cups Tim will have to buy to get the same number of each?

Tim is buying packages of paper plates and cups. He wants to have equal amounts of each, but plates come 24 per pack, and cups come 16 pe What is r pack.the least amount of plates and cups Tim will have to buy to get the same number of each?A.) 8

B.) 16

C.) 24

D.) 48

Step-by-step explanation:

The above query is to be solved via way of means of HCF .

  • HCF or Highest Common Factor is the best variety which divides every of the 2 or greater numbers.
  • HCF is likewise referred to as the Greatest Common Measure (GCM) and Greatest Common Divisor(GCD).

HENCE ,

elements of 16 = 2×2×2×2

elements of 24 = 2×2×2×3

HCF = 2×2×2×2×3

= 48

(#SPJ2)

Similar questions