Question

time = 10^9 sec charge= 2 sec find current​

Answer 1

$\color{darkblue}\underline{\underline{\sf Given-}}$

• Time (t) = ${\sf 10^9\:s}$
• Charge (Q) = 2 C

$\color{darkblue}\underline{\underline{\sf To \: Find-}}$

• Current (i)

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$\color{darkblue}\underline{\underline{\sf Formula \: Used-}}$

$\color{violet}\bullet\underline{\boxed{\sf i=\dfrac{dQ}{dt}}}$

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$\color{darkblue}\underline{\underline{\sf Solution-}}$

$\implies{\sf i=\dfrac{2}{10^9}}$

$\color{red}\implies{\sf i=2×10^{-9} A}$

$\color{darkblue}\underline{\underline{\sf Answer-}}$

Current is $\color{red}{\sf 2×10^{-9}A}$

Answer 2

$\mathtt{\huge{ \fbox{Solution :)}}}$

Given ,

• Time (t) = (10)^9 sec
• Charge (q) = 2 C

We know that ,

The rate of unit charge is called electric current

$\large \mathtt{ \fbox{Electric \: current \: (I) = \frac{q}{t} }}$

Thus,

I = 2/(10)^9

I = 2 × (10)^-9 amp

Hence , the electric current is 2 × (10)^-9 amp

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